Current through R

_{1}is I_{1 }and R_{2}is I_{2 }, while total current drawn from source is I_{T}.**.**I

^{.}._{T }= I

_{1 }+ I

_{2 }

But I

_{1 }= V/R_{1}, I_{2 }= V/R_{2}i.e. V =I

_{1 }R_{1}= I_{2 }R_{2}**.**I

^{.}._{1 }= I

_{2 }(R

_{2}/R

_{1})

**Key point**: In general, the current in any branch is equal to the ratio of opposite branch resistance to the total resistance value, multiplied by the total current in the circuit.

**Example**: Find the magnitude of total current, current through and if , R

_{1}= 10 Ω , R

_{2 }= 20 Ω and V = 50V.

The equivalent resistance of tow is,

R

_{eq}=(R_{1}R_{2}) / ( R_{1}+ R_{2}) = (10 x 20)/ (10 + 20) = 6.67 . I

_{T }= V/R_{eq}= 50/6.67 = 7.5 AIt can be verified that : I

_{T }= I_{1 }+ I_{2 }.
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