As tow resistors are connected in series, the current flowing through both the resistors is same, i.e. I. Then applying KVL, we get,

V= I R

_{1 }+I R_{2 } Total voltage applied is equal to the sum of voltage drops V

_{R1 }and V_{R2 }across R_{1 }and R_{2 }respectively.**.**V

^{.}._{R1 }= I R

_{1 }

Similarly, V

_{R2 }= I R_{2 }_{ }

_{ }

So this circuit is a voltage divider circuit.

**Key point**: So in general, voltage drop across any resistor, or combination of resistors, in a series circuit is equal to the ratio of that resistance value to the total resistance, multiplied by the source voltage.

**Example**: Find the voltage across the three resistances shown in the Fig.

**Solution :**

**Key point**: It can be seen that voltage across any resistance of series circuit is ratio of that resistance to the total resistance, multiplied by the source voltage.

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