We have seen previously that when load changes, for constant excitation, current drawn by the motor increases. But if excitation i.e. field current is changed keeping load constant, the synchronous motor reacts by by changing its power factor of operation. This is most interesting feature of synchronous motor. Let us see the details of such operation.

Consider a synchronous motor operating at a certain load. The corresponding load angle is δ.

At start, consider normal behaviour of the synchronous motor, where excitation is adjusted to get E

_{b }= V i.e. induced e.m.f. is equal to applied voltage. Such an excitation is called Normal Excitation of the motor. Motor is drawing certain current from the supply and power input to the motor is say P_{in}. The power factor of the motor is lagging in nature as shown in the Fig. 1(a).Now when excitation is changed, changes but there is hardly any change in the losses of the motor. So the power input also remains same for constant load demanding same power output.

Now P

_{in }= √3 V_{L }I_{L }cos Φ = 3 (V_{ph }I_{ph }cos Φ) Most of the times, the voltage applied to the motor is constant. Hence for constant power input as V

_{ph }is constant, 'I_{ph }cos Φ' remains constant.**Note**: So far this entire operation of variable excitation it is necessary to remember that the cosine component of armature current, I

_{a }cosΦ remains constant.

So motor adjusts its cos Φ i.e. p.f. nature and value so that I

_{a }cos Φ remains constant when excitation of the motor is changed keeping load constant. This is the reason why synchronous motor reacts by changing its power factor to variable excitation conditions.__1.1 Under Excitation__

When the excitation is adjusted in such a way that the magnitude of induced e.m.f. is less than the applied voltage (E

_{b }< V) the excitation is called Under Excitation. Due to this, E

_{R }increases in magnitude. This means for constant Z_{s}, current drawn by the motor increases. But E_{R }phase shifts in such a way that, phasor I_{a }also shifts (as E_{R ^}I_{a }= θ) to keep I_{a }cos Φ component constant. This is shown in the Fig. 1(b). So in under excited condition, current drawn by the motor increases. The p.f. cos Φ decreases and becomes more and more lagging in nature.__1.2 Over Excitation__

The excitation to the field winding for which the induced e.m.f. becomes greater than applied voltage (E

_{b }< V), is called over excitation. Due to increased magnitude of E

_{b}, E_{R }also increases in magnitude. But the phase of E_{R }also changes. Now = E_{R ^}I_{a }= θ_{ }is constant, hence I_{a }also changes its phase. So Φ changes. The I_{a }increases to keep I_{a }cos Φ constant as shown in Fig.1(c). The phase of E_{R }changes so that I_{a }becomes leading with respect to V_{ph }in over excited condition. So power factor of the motor becomes leading in nature. So overexcited synchronous motor works on leading power factor. So power factor decreases as over excitation increases but it becomes more and more leading in nature.__1.3 Critical Excitation__

When the excitation is changed, the power factor changes. The excitation for which the power factor of the motor is unity (cos Φ = 1) is called critical excitation. Then I

_{aph }is in phase with V_{ph}. Now I_{a }cos Φ must be constant, cos Φ = 1 is at its maximum hence motor has to draw minimum current from supply for unity power factor condition. So for critical excitation, cos Φ = 1 and current drawn by the motor is minimum compared to current drawn by the motor for various excitation conditions. This is shown in the Fig. 1(d).

Fig. 1 Constant load variable excitation operation |

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ردحذفSir objective type question banaiye ...👏👏

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