The potential difference between any two points is nothing but the work done in joules per coulomb required to move a coulomb of charge between the two points. The force on a charge in the field is measured by electric field intensity which is equal to the force in newtons per coulomb on a coulomb charge at the point considered and is measured in volts per meter.

Consider two points P

_{1 }and P_{2 }located at a distance of D_{1 }and D_{2 }from centre of wire. There is positive charge on wire which will repel when a positive charge is placed in the field. If we want to move charge from point P_{2 }to P_{1 }then work must be done on positive charge. Here P_{1 }is at higher potential than P_{2}. If the charge moves from P_{1 }to P_{2}, it expends energy which is nothing but voltage drop from P_{1 }to P_{2}. The path followed does not affect the potential difference. In order to find the voltage drop from P

The voltage drop between P_{1 }to P_{2 }is to obtain the voltage between equipotential surfaces passing through P_{1 }and P_{2}._{1}and P

_{2 }is,

The voltage drop between two points may be either positive or negative depending upon the charge causing the potential difference is positive or negative. It also depends upon whether the voltage drop is computed from a point near the conductor to a point far away or vice versa.

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