Now consider that a capacitor 'C' is being discharged through a resistor R by closing the switch at t = 0. At the time of closing the switch the capacitor 'C' is fully charged to V volts and it discharges through resistance 'R' and current through resistance flows in opposite direction to that at the time of charging.

As time passes, charge and hence the capacitor voltage V

The variation of capacitor voltage and discharging current as a function of time is shown in the Fig. 2._{C}decreases gradually and hence discharge current also gradually decreases exponentially from maximum to zero.
As direction of current is opposite to that of charging current, it is mathematically considered as negative. Hence graph of current against time is in fourth quadrant.

__1. Mathematical Analysis__

Applying Kirchhoff's voltage law, we had

Integrating both sides

**Note**: The negative sign indicates that the direction of the discharge current is the reverse of that charging current.

__2. Time Constant__

Similar to the previous definition, at the time of discharging also the term CR is called as time constant denoted by Ԏ.

i) The time required for capacitor voltage to fall to 0.368 of its initial maximum value on discharge from its initial maximum value.

ii) The time required during which the capacitor discharge current falls to 0.368 of its initial maximum value.

__3. Significance of Time Constant__

The charging and discharging of a capacitor under the conditions discussed is said to be exponential. The 'time constant' (Ԏ) of the circuit has following significance.

i) The whole charging or discharging process can be considered to be completed in a time equal to 4 times the time constant and the current falls to insignificant value (Theoretically the process takes infinite time).
ii) The charge current falls to 36.8% of its initial value in a time equal to time constant (Ԏ) and to nearly 1.8% of initial value in t = 4 Ԏ.

iii) The capacitor charges to nearly 63.2% of its value in t = Ԏ and nearly 98.2% of the final value in t = 4 Ԏ provided it is initially uncharged.iv) The capacitor discharges to nearly 36.8% of its initial value in t = Ԏ and nearly 1.8% of its initial value in t = 4 Ԏ.

It's Looks deeply awesome article!!which you have posted is useful.

ReplyDeleteIELTS Coaching in Anna Nagar

German Classes in Anna Nagar

Spoken English Class in Anna Nagar

French Classes in Anna Nagar

AWS Training in Anna Nagar

Outstanding as well as powerful recommendation by the writer of this blog are truly practical to me. Hydroponic Store Canada

ReplyDelete